Notifications
Clear all
Triangles
1
Posts
2
Users
0
Likes
501
Views
0
12/07/2021 12:05 pm
Topic starter
BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.
1 Answer
0
12/07/2021 12:06 pm
It is known that BE and CF are two equal altitudes.
Now, in ΔBEC and ΔCFB,
BEC = CFB = 90° (Same Altitudes)
BC = CB (Common side)
BE = CF (Common side)
ΔBEC ΔCFB by RHS congruence criterion.
C = B (by CPCT)
Therefore, AB = AC as sides opposite to the equal angles is always equal.