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In Figure, B < A and C < D. Show that AD < BC.

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In Figure, B < A and C < D. Show that AD < BC.

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In the question, it is mentioned that angles B and angle C is smaller than angles A and D respectively i.e. B < A and C < D.

Since the side opposite to the smaller angle is always smaller

AO < BO — (i)

And OD < OC —(ii)

By adding equation (i) and equation (ii) we get

AO + OD < BO + OC

AD < BC

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