In Figure, B < A and C < D. Show that AD < BC.
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12/07/2021 12:21 pm
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In Figure, B < A and C < D. Show that AD < BC.
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12/07/2021 12:22 pm
In the question, it is mentioned that angles B and angle C is smaller than angles A and D respectively i.e. B < A and C < D.
Since the side opposite to the smaller angle is always smaller
AO < BO — (i)
And OD < OC —(ii)
By adding equation (i) and equation (ii) we get
AO + OD < BO + OC
AD < BC
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