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12/07/2021 12:08 pm
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ABC is an isosceles triangle with AB = AC. Draw AP ⊥ BC to show that B = C.
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12/07/2021 12:09 pm
In the question, it is given that AB = AC
Now, ΔABP and ΔACP are similar by RHS congruency as
APB = APC = 90° (AP is altitude)
AB = AC (Given in the question)
AP = AP (Common side)
ΔABP ΔACP.
∴ B = C (by CPCT)