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24/05/2021 10:57 am
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Simplify:
(i) 22/3× 21/5
(ii) (1/33)7
(iii) 111/2/111/4
(iv) 71/2× 81/2
1 Answer
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24/05/2021 10:58 am
(i) 22/3 × 21/5
22/3×21/5 = 2(2/3)+(1/5) [⸪Since, am×an = am+n____ Laws of exponents]
= 213/15 [⸪ 2/3 + 1/5 = (2×5+3×1)/(3×5) = 13/15]
(ii) (1/33)7
(1/33)7 = (3-3)7 [⸪Since,(am)n = am x n____ Laws of exponents]
= 3-21
(iii) 111/2/111/4
111/2/111/4 = 11(1/2)-(1/4)
= 111/4 [⸪(1/2) – (1/4) = (1×4-2×1)/(2×4) = 4-2)/8 = 2/8 = ¼ ]
(iv) 71/2×81/2
71/2×81/2 = (7×8)1/2 [⸪Since, (am×bm = (a×b)m ____ Laws of exponents]
= 561/2