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Find: (i) 9^3/2 (ii) 32^2/5 (iii) 16^3/4 (iv) 125^-1/3

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Find:

(i) 93/2

(ii) 322/5

(iii) 163/4

(iv) 125-1/3

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(i) 93/2

93/2 = (3×3)3/2

= (32)3/2

= 33 [⸪2×3/2 = 3]

=27

(ii) 322/5

322/5 = (2×2×2×2×2)2/5

= (25)2⁄5

= 22 [⸪5×2/5= 2]

= 4

(iii)163/4

163/4 = (2×2×2×2)3/4

= (24)3⁄4

= 23 [⸪ 4 × 3/4 = 3]

= 8

(iv) 125-1/3

125-1/3 = (5 × 5 × 5)-1/3

= (53)-1⁄3

= 5-1 [⸪ 3 × -1/3 = -1]

= 1/5

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