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Find: (i) 64^1/2 (ii) 32^1/5 (iii) 125^1/3
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24/05/2021 10:50 am
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Find:
(i) 64^{1/2}
(ii) 32^{1/5}
(iii) 125^{1/3}
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24/05/2021 10:51 am
(i) 64^{1/2}
64^{1/2} = (8 × 8)^{1/2}
= (8^{2})^{½}
= 8^{1} [⸪ 2 ×1/2 = 2/2 =1]
= 8
(ii) 32^{1/5}
32^{1/5 }= (2^{5})^{1/5}
= (2^{5})^{⅕}
= 2^{1} [⸪ 5 × 1/5 = 1]
= 2
(iii)125^{1/3}
(125)^{1/3} = (5 ×5× 5)^{1/3}
= (5^{3})^{⅓}
= 5^{1} (3 × 1/3 = 3/3 = 1)
= 5
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