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Find: (i) 64^1/2 (ii) 32^1/5 (iii) 125^1/3

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Find:

(i) 641/2

(ii) 321/5

(iii) 1251/3

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(i) 641/2

641/2 = (8 × 8)1/2

= (82)½

= 81 [⸪ 2  ×1/2 = 2/2 =1]

= 8

(ii) 321/5

321/5 = (25)1/5

= (25)

= 21 [⸪ 5 × 1/5 = 1]

= 2

(iii)1251/3

(125)1/3 = (5   ×5× 5)1/3

= (53)

= 51 (3 × 1/3 = 3/3 = 1)

= 5

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