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Find: (i) 9^3/2 (ii) 32^2/5 (iii) 16^3/4 (iv) 125^-1/3
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24/05/2021 10:53 am
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Find:
(i) 93/2
(ii) 322/5
(iii) 163/4
(iv) 125-1/3
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24/05/2021 10:55 am
(i) 93/2
93/2 = (3×3)3/2
= (32)3/2
= 33 [⸪2×3/2 = 3]
=27
(ii) 322/5
322/5 = (2×2×2×2×2)2/5
= (25)2⁄5
= 22 [⸪5×2/5= 2]
= 4
(iii)163/4
163/4 = (2×2×2×2)3/4
= (24)3⁄4
= 23 [⸪ 4 × 3/4 = 3]
= 8
(iv) 125-1/3
125-1/3 = (5 × 5 × 5)-1/3
= (53)-1⁄3
= 5-1 [⸪ 3 × -1/3 = -1]
= 1/5
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