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Find: (i) 64^1/2 (ii) 32^1/5 (iii) 125^1/3
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24/05/2021 10:50 am
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Find:
(i) 641/2
(ii) 321/5
(iii) 1251/3
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24/05/2021 10:51 am
(i) 641/2
641/2 = (8 × 8)1/2
= (82)½
= 81 [⸪ 2 ×1/2 = 2/2 =1]
= 8
(ii) 321/5
321/5 = (25)1/5
= (25)⅕
= 21 [⸪ 5 × 1/5 = 1]
= 2
(iii)1251/3
(125)1/3 = (5 ×5× 5)1/3
= (53)⅓
= 51 (3 × 1/3 = 3/3 = 1)
= 5
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