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In an isosceles triangle ABC, with AB = AC, the bisectors of B and C intersect each other at O. Join A to O.

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In an isosceles triangle ABC, with AB = AC, the bisectors of B and C intersect each other at O. Join A to O. Show that:

(i) OB = OC

(ii) AO bisects A

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AB = AC and

the bisectors of B and C intersect each other at O

(i) Since ABC is an isosceles with AB = AC

B = C

\(\frac{1}{2}\) B = \(\frac{1}{2}\) C

⇒ OBC = OCB (Angle bisectors)

∴ OB = OC (Side opposite to the equal angles are equal.)

(ii) In ΔAOB and ΔAOC,

AB = AC (Given in the question)

AO = AO (Common arm)

OB = OC (As Proved Already)

So, ΔAOB ΔAOC by SSS congruence condition.

BAO = CAO (by CPCT)

Thus, AO bisects A.

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