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03/06/2021 12:26 pm
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In the figure, QR/QS = QT/PR and ∠1 = ∠2. Show that ΔPQS ~ ΔTQR.
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03/06/2021 12:27 pm
In ΔPQR,
∠PQR = ∠PRQ
∴ PQ = PR ………………(i)
Given,
QR/QS = QT/PR Using equation (i), we get
QR/QS = QT/QP ………….(ii)
In ΔPQS and ΔTQR, by equation (ii),
QR/QS = QT/QP
∠Q = ∠Q
∴ ΔPQS ~ ΔTQR [By SAS similarity criterion]