In the figure, if LM || CB and LN || CD, prove that AM/AB = AN/AD
Triangles
1
Posts
2
Users
0
Likes
326
Views
Add a comment
1 Answer
0
02/06/2021 12:01 pm
In the given figure, we can see, LM || CB,
By using basic proportionality theorem, we get,
AM/AB = AL/AC …………..(i)
Similarly, given, LN || CD and using basic proportionality theorem,
∴ AN/AD = AL/AC ……………(ii)
From equation (i) and (ii), we get,
AM/AB = AN/AD
Hence, proved.
Add a comment
Add a comment
Forum Jump:
Related Topics
-
Nazima is fly fishing in a stream. The tip of her fishing rod is 1.8 m above the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod.
4 years ago
-
In Figure, D is a point on side BC of ∆ ABC such that BD/CD = AB/AC. Prove that AD is the bisector of ∠BAC.
4 years ago
-
In Figure, two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. Prove that: (i) ∆ PAC ~ ∆ PDB (ii) PA.PB = PC.PD.
4 years ago
-
In Figure, two chords AB and CD intersect each other at the point P. Prove that : (i) ∆APC ~ ∆ DPB (ii) AP.PB = CP.DP
4 years ago
-
Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides.
4 years ago
Forum Information
- 321 Forums
- 27.3 K Topics
- 53.8 K Posts
- 92 Online
- 12.4 K Members
Our newest member: Stripchat
Forum Icons:
Forum contains no unread posts
Forum contains unread posts
Topic Icons:
Not Replied
Replied
Active
Hot
Sticky
Unapproved
Solved
Private
Closed