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03/06/2021 12:33 pm
Given, ΔABE ≅ ΔACD.
∴ AB = AC [By CPCT] ……………….(i)
And, AD = AE [By CPCT] ………………(ii)
In ΔADE and ΔABC, dividing eq.(ii) by eq(i),
AD/AB = AE/AC
∠A = ∠A [Common angle]
∴ ΔADE ~ ΔABC [SAS similarity criterion]