ABC is an isosceles triangle with AC = BC. If AB^2 = 2AC^2, prove that ABC is a right triangle.
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04/06/2021 12:28 pm
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ABC is an isosceles triangle with AC = BC. If AB2 = 2AC2, prove that ABC is a right triangle.
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04/06/2021 12:30 pm
Given, ΔABC is an isosceles triangle having AC = BC and AB2 = 2AC2
In ΔACB,
AC = BC
AB2 = 2AC2
AB2 = AC2 + AC2
= AC2 + BC2 [Since, AC = BC]
Hence, by Pythagoras theorem ΔABC is right angle triangle.
This post was modified 4 years ago by Raavi Tiwari
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