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04/06/2021 12:25 pm
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ABC is an isosceles triangle right angled at C. Prove that AB2 = 2AC2.
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04/06/2021 12:26 pm
Given, ΔABC is an isosceles triangle right angled at C.
In ΔACB, ∠C = 90°
AC = BC (By isosceles triangle property)
AB2 = AC2 + BC2 [By Pythagoras theorem]
= AC2 + AC2 [Since, AC = BC]
AB2 = 2AC2
This post was modified 4 years ago by Raavi Tiwari