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If the solubility product of CuS is 6 x 10^-16, calculate the maximum molarity of CuS in aqueous solution.

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If the solubility product of CuS is 6 x 10-16, calculate the maximum molarity of CuS in aqueous solution.

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The Solubility product of CuS,

Ksp = 6 × 10-16

Let s be the solubility of CuS in mol L-1.

CuS → Cu2+ + S2-

Now, Ksp = [Cu2+][S2-]

= s × s

= s2

we have, Ksp = s2 = 6 × 10-16

⇒ s = \(\sqrt{6 \times 10^{-16}}\)

= 2.45 × 10-8 mol L-1

Hence, the maximum molarity of CuS in an aqueous solution is 2.45 × 10-8 mol L-1.

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