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08/01/2022 6:01 pm
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Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 liter of water at 25°C, assuming that it is completely dissociated.
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08/01/2022 6:06 pm
When K2SO4 is dissolved in water, ions are produced.
Total number of ions produced = 3
i = 3
Given,
w = 25 mg = 0.025 g
V = 2 L
T = 25°C = (25 + 273) K = 298 K
Also, we know that:
R = 0.0821 L atm K-1 mol-1
M = (2 × 39) + (1 × 32) + (4 × 16)
= 174 g mol-1
Appling the following relation,
π = i\(\frac{n}{v}\)RT
= i\(\frac{w}{M}\)\(\frac{1}{v}\)RT
= 3 x \(\frac{0.025}{174}\)x \(\frac{1}{2}\) x 0.0821 x 298
= 5.27 x 10-3 atm