Notifications
Clear all
0
06/01/2022 2:35 pm
Topic starter
If the solubility product of CuS is 6 x 10-16, calculate the maximum molarity of CuS in aqueous solution.
1 Answer
0
06/01/2022 2:41 pm
The Solubility product of CuS,
Ksp = 6 × 10-16
Let s be the solubility of CuS in mol L-1.
CuS → Cu2+ + S2-
Now, Ksp = [Cu2+][S2-]
= s × s
= s2
we have, Ksp = s2 = 6 × 10-16
⇒ s = \(\sqrt{6 \times 10^{-16}}\)
= 2.45 × 10-8 mol L-1
Hence, the maximum molarity of CuS in an aqueous solution is 2.45 × 10-8 mol L-1.
This post was modified 3 years ago by admin