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At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

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At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

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Here, T = 300 K

π = 1.52 bar

R = 0.083 bar L K-1 mol-1

Applying the relation,

π = CRT

⇒ C = \(\frac{\pi}{RT}\)

= \(\frac{1.52\ Bar}{0.083 \ bar L K^{-1}mol^{-1} \times 300K}\)

= 0.061 mol

Since the volume of the solution is 1 L, the concentration of the solution would be 0.061 M.

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