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05/01/2022 5:15 pm
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At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?
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05/01/2022 5:19 pm
Here, T = 300 K
π = 1.52 bar
R = 0.083 bar L K-1 mol-1
Applying the relation,
π = CRT
⇒ C = \(\frac{\pi}{RT}\)
= \(\frac{1.52\ Bar}{0.083 \ bar L K^{-1}mol^{-1} \times 300K}\)
= 0.061 mol
Since the volume of the solution is 1 L, the concentration of the solution would be 0.061 M.