Notifications
Clear all
0
27/01/2022 4:58 pm
Topic starter
The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.
1 Answer
0
27/01/2022 5:02 pm
k = \(\frac{0.693}{t_{1/2}}\)
Here,
= \(\frac{0.693}{5730}\)years-1
It is know that
t = \(\frac{2.303}{k}\)log \(\frac{[R]_0}{[R]}\)
= \(\frac{2.303}{\frac{0.693}{5730}}\)log \(\frac{100}{80}\)
= 1845 years (approximately)
Hence, the age of the sample is 1845 years.