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[Solved] The rate constant for a first order reaction is 60 s^-1. How much time will it take to reduce the initial concentration of the reactant to its 1/16th value?

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The rate constant for a first order reaction is 60 s-1. How much time will it take to reduce the initial concentration of the reactant to its 1/16th value?

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It is known that,

t = \(\frac{2.303}{k}\)log \(\frac{[R]_0}{[R]}\)

= \(\frac{2.303}{60\;s^{-1}}\)log \(\frac{1}{\frac{1}{16}}\)

= \(\frac{2.303}{60\;s^{-1}}\)log 16

= 4.6 x 10-2 (approximately)

Hence, the required time is 4.6 x 10-2s.

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