[Solved] The decomposition of hydrocarbon follows the equation k = (4.5 x 10^11 s^1) e^28000 K/T Calculate Ea.
The decomposition of hydrocarbon follows the equation
k = (4.5 x 10^{11} s^{1}) e^{28000 K/T}
Calculate E_{a}.
The given equation is
k = (4.5 × 10^{11} s^{1}) e^{28000 K/T} (i)
Arrhenius equation is given by,
k = Ae^{Ea/RT}(ii)
From equation (i) and (ii), we obtain
\(\frac{E_a}{RT}\) = \(\frac{28000K}{T}\)
⇒ E_{a }= R x 28000 K
= 8.314 J K^{1 }mol^{1} × 28000 K
= 232792 J mol^{1}
= 232.792 kJ mol^{1}

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