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The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?

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The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?

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Given: Distance of far point = 80 cm, P= ?

For viewing far-off objects, the focal length of corrective lens,

f = -80 cm

∴ Power, P = \(\frac{100}{f}\) = \(\frac{100}{-80}\)

= -1.25 D

The negative sign shows that the lens is concave.

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