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25/09/2021 7:01 pm
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The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?
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25/09/2021 7:03 pm
Given: Distance of far point = 80 cm, P= ?
For viewing far-off objects, the focal length of corrective lens,
f = -80 cm
∴ Power, P = \(\frac{100}{f}\) = \(\frac{100}{-80}\)
= -1.25 D
The negative sign shows that the lens is concave.