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A hemispherical tank is made up of an iron sheet 1cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank.
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31/07/2021 11:21 am
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A hemispherical tank is made up of an iron sheet 1cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank. (Assume π = 22/7)
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31/07/2021 11:23 am
Inner Radius of the tank, (r) = 1m
Outer Radius (R ) = 1.01m
Volume of the iron used in the tank = \(\frac{2}{3}\) π(R3– r3)
Put values,
Volume of the iron used in the hemispherical tank
= \(\frac{2}{3}\) × \(\frac{22}{7}\) × (1.013– 13)
= 0.06348
So, volume of the iron used in the hemispherical tank is 0.06348 m3.
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