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A hemispherical tank is made up of an iron sheet 1cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank.

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A hemispherical tank is made up of an iron sheet 1cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank. (Assume π = 22/7)

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Inner Radius of the tank, (r) = 1m

Outer Radius (R ) = 1.01m

Volume of the iron used in the tank = \(\frac{2}{3}\) π(R3– r3)

Put values,

Volume of the iron used in the hemispherical tank

= \(\frac{2}{3}\) × \(\frac{22}{7}\) × (1.013– 13)

= 0.06348

So, volume of the iron used in the hemispherical tank is 0.06348 m3.

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