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Structure of Atom
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19/08/2021 1:14 pm
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The total spin and magnetic moment for the atom with atomic number 24 are:
(a) \(\pm 3, \sqrt{48}\)BM
(b) \(\pm 3, \sqrt{35}\)BM
(c) \(\pm \frac{3}{2}, \sqrt{48}\)BM
(d) \(\pm \frac{3}{2}, \sqrt{35}\)BM
1 Answer
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19/08/2021 1:18 pm
Correct answer: (a) \(\pm 3, \sqrt{48}\)BM
Explanation:
Atomic number = 24
Electronic configuration is 3d5, 4s1
No. of valence e–1(s) = 6
Total spin = \(\pm \frac{1}{2}\) x 6 = ±3
Magnetic moment
= \(\sqrt{n(n + 2)}\) = \(\sqrt{6(6 + 2)}\)
= \(\pm 3, \sqrt{48}\)BM