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An electron travels with a velocity of x ms^-1. For a proton to have the same de-Broglie wavelength, the velocity will be approximately :

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An electron travels with a velocity of x ms-1. For a proton to have the same de-Broglie wavelength, the velocity will be approximately :

(a) \(\frac{1840}{x}\)

(b) \(\frac{x}{1840}\)

(c) 1840 x

(d) x

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Correct answer: \(\frac{x}{1840}\)

Explanation:

λ = \(\frac{h}{m_ex}\) 

= \(\frac{h}{m_pV}\) = \(\frac{h}{1840\; m_e}\)

[∴ \(m_p = 1840\; m_e\) ]

Hence, V = \(\frac{x}{1840}\)

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