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19/08/2021 1:06 pm
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An electron travels with a velocity of x ms-1. For a proton to have the same de-Broglie wavelength, the velocity will be approximately :
(a) \(\frac{1840}{x}\)
(b) \(\frac{x}{1840}\)
(c) 1840 x
(d) x
1 Answer
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19/08/2021 1:10 pm
Correct answer: \(\frac{x}{1840}\)
Explanation:
λ = \(\frac{h}{m_ex}\)
= \(\frac{h}{m_pV}\) = \(\frac{h}{1840\; m_e}\)
[∴ \(m_p = 1840\; m_e\) ]
Hence, V = \(\frac{x}{1840}\)