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07/01/2022 4:30 pm
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Henry's law constant for the molality of methane in benzene at 298 K is 4.27 x 105 mm Hg. Calculate the solubility of methane in benzene at 298 Kunder 760 mm Hg.
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07/01/2022 4:37 pm
Here,
p = 760 mm Hg
kH = 4.27 × 105 mm Hg
According to Henry's law,
p = kHx
⇒ x = \(\frac{p}{k_H}\)
= \(\frac{760\ mm \ Hg}{4.27 \times 10^5 \ mm \ Hg}\)
= 177.99 × 10-5
= 178 × 10-5 (approximately)
Hence, the mole fraction of methane in benzene is 178 × 10-5.