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02/01/2022 5:07 pm
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Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.
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02/01/2022 5:11 pm
Given,
Volume of water, V = 450 mL
= 0.45 L
Temperature, T = (37 + 273) K
= 310 K
Number of moles of the polymer, n = \(\frac{1}{185000}\) mol
We know that,
Osmotic pressure, π = \(\frac{n}{V}\)RT
= \(\frac{1}{185000}\) mol x \(\frac{1}{0.45L}\) x \(8.314 \times 10^3\)\(Pa\;L\;K^{-1}mol^{-1}\) x 310K
= 30.98 Pa
= 31 Pa (approximately)
This post was modified 3 years ago by admin