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31/12/2021 3:24 pm
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Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.
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31/12/2021 3:29 pm
Mass percentage of C6H6 = \(\frac{Mass\;of\;C_6H_6}{Total\;mass\;of\;the\;solution}\) x 100%
= \(\frac{Mass\;of\;C_6H_6}{Mass\;of\;C_6H_6 + Mass\;of\;CCl_4}\) x 100%
= \(\frac{22}{22 + 122}\) x 100%
= 15.28%
Mass percentage of CCl4 = \(\frac{Mass\;of\;CCl_4}{Total\;mass\;of\;the\;solution}\) x 100%
= \(\frac{Mass\;of\;CCl_4}{Mass\;of\;C_6H_6 + Mass\;of\;CCl_4}\) x 100%
= \(\frac{122}{22 + 122}\) x 100%
= 84.72%
Alternatively,
Mass percentage of CCl4 = (100 - 15.28)%
= 84.72%