Check whether 6^n can end with the digit 0 for any natural number n.
Check whether 6n can end with the digit 0 for any natural number n.
If the number 6n ends with the digit zero (0), then it should be divisible by 5, as we know any number with unit place as 0 or 5 is divisible by 5.
Prime factorization of 6n = (2×3)n
Therefore, the prime factorization of 6n doesn’t contain prime number 5.
Hence, it is clear that for any natural number n,6n is not divisible by 5 and thus it proves that 6n cannot end with the digit 0 for any natural number n.
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The following real numbers have decimal expansions as given below. In each case, decide whether they are rational or not. If they are rational, and of the form, p q what can you say about the prime factors of q? (i) 43.123456789 (ii) 0.120120012000...
1 year ago
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Without actually performing the long division, state whether the following rational numbers (i) 23/(2^35^2) (ii) 129/(2^25^77^5) (iii) 6/15 (iv) 35/50
1 year ago
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Without actually performing the long division, state whether the following rational numbers will have a terminating decimal expansion or a non-terminating repeating decimal expansion: (i) 13/3125 (ii) 17/8 (iii) 64/455
1 year ago
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Prove that the following are irrationals: (i) 1/√2 (ii) 7√5 (iii) 6 + √2
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Prove that 3 + 2√5 is irrational.
1 year ago
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