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05/01/2021 4:10 pm
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A train is travelling at a speed of 90 km h-1. Brakes are applied so as to produce a uniform acceleration of -0.5 m s-2. Find how far the train will go before it is brought to rest.
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05/01/2021 4:18 pm
Here, initial speed,
u = 90 km h-1 = \(\frac{90 \times 1000}{60 \times 60 s}\)
Acceleration, a = -0.5 ms-2
final velocity, v = 0
From v2 - u2 = 2as,
Distance travelled
s = \(\frac{v^2 -u^2}{2a}\) = \(\frac{0 -(25)^2}{2 \times (-0.5)}\)
= 625 m