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A car is travelling along the road at 8 ms^-1. It accelerates at 1 ms^-2 for a distance of 18 m. How fast is it than travelling?

  

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A car is travelling along the road at 8 ms-1. It accelerates at 1 ms-2 for a distance of 18 m. How fast is it than travelling?

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Initial velocity, u = 8 m/s

Acceleration, a = 1 m/s2

Distance, s = 18 m

Using relation, v2 = u2 + 2as

v2 = (8)2 + 2 x 1 x 18

v2 = 64 + 36 = 100

v = \(\sqrt{100}\) = 10 m/s

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