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05/01/2021 4:34 pm
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A stone is thrown in vertically upward direction with a velocity of 5 m s-1. If the acceleration of the stone during its motion is 10 m s-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
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05/01/2021 4:42 pm
u = 5 m s-1, v = 0, a = -10 m s-2
(i) v = u + at
0 = 5 + (-10) t
-5 = -10 t
∴ t = 5/10 = 0.5 s
(ii) v2 - u2 = 2as
(0)2 - (5)2 = 2(-10) x s
-25 = -20 x s
∴ s = 25/20 = 1.25 m