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03/01/2021 5:23 pm
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A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?
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03/01/2021 5:46 pm
A figure ABCD is a square field of side 10 m.
Time for one round = 40 s
Total time = 2 min 20 s
= (2 x 60 + 20)s = 140 s
Number of round completed = \(\frac{140}{40}\) = 3.5
If farmer starts from A, it will complete 3 rounds(A → B→ C→ D→ A)at A.
In the last 0.5 round starting form A, he will finish at C.
Displacement of farmer
AC = \(\sqrt{AB^2 + AC^2}= \sqrt{10^2 + 10^2}\)
= 10\(\sqrt{2}m\)
This post was modified 4 years ago by admin