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24/10/2021 8:08 pm
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A car acquires a velocity of 72 km per hour in 10 seconds starting from rest. Find (i) the acceleration, (ii) the average velocity, and (iii) the distance travelled in this time.
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24/10/2021 8:16 pm
Initial velocity, u = 0 m/s
Final velocity, v = 72 km/h = 20 m/s
Time, t = 10s
(i) Acceleration = \(\frac{Final\;velocity-Initial\;velocity}{Time\;taken}\)
So, a = \(\frac{v -u}{t}\) = \(\frac{20 -0}{10}\)
= \(\frac{20}{10}\) m/s2 = 2 m/s2
(ii) Average velocity = \(\frac{Initial\;velocity + Final\;velocity}{2}\)
= \(\frac{0 + 20}{2}\) = \(\frac{20}{2}\)m/s
= 10 m/s
(iii) Distance travelled = Average velocity x Time
= 10 m/s x 10s = 100 m