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In Figure, if AB DE...

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# In Figure, if AB DE, BAC = 35° and CDE = 53°, find DCE.

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In Figure, if AB DE, BAC = 35° and CDE = 53°, find DCE.

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We know that AE is a transversal since AB DE

Here BAC and AED are alternate interior angles.

Hence, BAC = AED

It is given that BAC = 35°

AED = 35°

Now consider the triangle CDE. We know that the sum of the interior angles of a triangle is 180°.

∴ DCE + CED + CDE = 180°

Putting the values, we get

DCE + 35° + 53° = 180°

Hence, DCE = 92°

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