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10/07/2021 12:38 pm
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In Figure, if AB DE, BAC = 35° and CDE = 53°, find DCE.
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10/07/2021 12:39 pm
We know that AE is a transversal since AB DE
Here BAC and AED are alternate interior angles.
Hence, BAC = AED
It is given that BAC = 35°
AED = 35°
Now consider the triangle CDE. We know that the sum of the interior angles of a triangle is 180°.
∴ DCE + CED + CDE = 180°
Putting the values, we get
DCE + 35° + 53° = 180°
Hence, DCE = 92°