The taxi fare in a city is as follows: For the first kilometer, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km.
The taxi fare in a city is as follows: For the first kilometer, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.
Total distance covered = x
Total fare = y
Fare for the first kilometer = 8 per km
Fare after the first 1km = 5 per km
If x is the total distance, then the distance after one km = (x1)km
i.e., Fare after the first km = 5(x  1)
According to the question,
The total fare = Fare of first km+ fare after the first km
y = 8 + 5(x1)
y = 8 + 5(x1)
y = 8 + 5x – 5
y = 5x + 3
Solving the equation,
When x = 0,
y = 5x + 3
y = 5 × 0 + 3
y = 3
When y = 0,
y = 5x+3
o = 5x+3
5x = 3
x = 3/5
x → 0, 3/5
y → 3, 0
The points to be plotted are (0, 3) and (3/5, 0)

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