(i) sin 60° cos 30° + sin 30° cos 60°

First, find the values of the given trigonometric ratios

sin 30° = 1/2

cos 30° = √3/2

sin 60° = 3/2

cos 60°= 1/2

Now, substitute the values in the given problem

sin 60° cos 30° + sin 30° cos 60°

= √3/2 ×√3/2 + (1/2) ×(1/2 )

= 3/4+1/4 = 4/4 = 1

(ii) 2 tan² 45° + cos² 30° – sin² 60

We know that, the values of the trigonometric ratios are:

sin 60° = √3/2

cos 30° = √3/2

tan 45° = 1

Substitute the values in the given problem

2 tan² 45° + cos² 30° – sin² 60 = 2(1)² + (√3/2)²-(√3/2)²

2 tan² 45° + cos² 30° – sin² 60 = 2 + 0

2 tan² 45° + cos² 30° – sin² 60 = 2