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Introduction to Trigonometry
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16/06/2021 11:51 am
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Evaluate:
(1 + tan2A/1 + cot2A) = (1 - tan A/1 - cot A)2 = tan2A
1 Answer
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16/06/2021 11:52 am
(1+tan2A/1+cot2A) = (1-tan A/1-cot A)2 = tan2A
L.H.S. = (1+tan2A/1+cot2A)
Since cot function is the inverse of tan function,
= (1+tan2A/1 + 1/tan2A)
= 1+tan2A/[(1+tan2A)/tan2A]
Now cancel the 1 + tan2A terms, we get
= tan2A
(1+tan2A/1+cot2A) = tan2A
(1-tan A/1-cot A)2 = tan2A
Hence proved