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Evaluate: (i) (sin^2 63° + sin^2 27°)/(cos^2 17° + cos^2 73°) (ii) sin 25° cos 65° + cos 25° sin 65°

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Evaluate:

(i) \(\frac{sin^2 63° + sin^2 27°}{cos^2 17° + cos^2 73°}\)

(ii)  sin 25° cos 65° + cos 25° sin 65°

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(i) \(\frac{sin^2 63° + sin^2 27°}{cos^2 17° + cos^2 73°}\)

= \(\frac{sin^2 (90°-27°) + sin^2 27°}{cos^2 (90°-73°) + cos^2 73°}\)

= \(\frac{sin^2 27° + sin^2 27°}{cos^2 27° + cos^2 73°}\)

= 1/1 = 1 (since sin2A + cos2A = 1)

Therefore, \(\frac{sin^2 63° + sin^2 27°}{cos^2 17° + cos^2 73°}\) = 1

(ii) sin 25° cos 65° + cos 25° sin 65°

= sin(90°-25°) cos 65° + cos (90°-65°) sin 65°

= cos 65° cos 65° + sin 65° sin 65°

= cos265° + sin265° = 1 (since sin2A + cos2A = 1)

Therefore, sin 25° cos 65° + cos 25° sin 65° = 1

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