Forum

A hammer of mass 50...
 
Notifications
Clear all

A hammer of mass 500 g, moving at 50 m s^-1, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer?

1 Posts
2 Users
0 Likes
330 Views
0
Topic starter

A hammer of mass 500 g, moving at 50 m s-1, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer?

1 Answer
0

The force of nail on the hammer,

F = \(\frac{Change\;in\;momentum\;of\;hammer}{Time}\)

F = \(\frac{m(v -u)}{t}\)

= \(\frac{0.50\;kg(0-50 \;ms^{-1})}{0.01\;s}\)

= -2500 N

Minus sign denotes the force exerted by the nail on the hammer is acting in the direction opposite to that of hammer.

Share:

How Can We Help?