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25/01/2022 3:44 pm
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The decomposition of dimethyl ether leads to the formation of CH4, H2 and CO and the reaction rate is given by Rate = k [CH3OCH3]3/2
The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e.,
Rate = k(pCH3OCH3)3/2
If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?
1 Answer
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25/01/2022 3:48 pm
If pressure is measured in bar and time in minutes, then
Unit of rate = bar min-1
Rate = k(pCH3OCH3)3/2
⇒ k = \(\frac{Rate}{(pCH_3OCH_3)^{\frac{3}{2}}}\)
Therefore, unit of rate constants k = \(\frac{bar \; min^{-1}}{bar^{3/2}}\)
= bar-1/2 min-1