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26/01/2022 6:21 pm
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A reaction is first order in A and second order in B.
(i) Write the differential rate equation.
(ii) How is the rate affected on increasing the concentration of B three times?
(iii) How is the rate affected when the concentrations of both A and B are doubled?
1 Answer
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26/01/2022 6:24 pm
(i) The differential rate equation will be
-\(\frac{d[R]}{dt}\) = k[A][B]2
(ii) If the concentration of B is increased three times, then
-\(\frac{d[R]}{dt}\) = k[A][3B]2
= 9.k[A][B]2
Therefore, the rate of reaction will increase 9 times.
(iii) When the concentrations of both A and B are doubled,
-\(\frac{d[R]}{dt}\) = k[A][B]2
= k[2A][2B]2
= 8.k[A][B]2
Therefore, the rate of reaction will increase 8 times.