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28/01/2022 5:48 pm
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A first order reaction takes 40 min for 30% decomposition. Calculate t1/2.
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28/01/2022 5:53 pm
Given
First order reaction,
t = \(\frac{2.303}{k}\) log \(\frac{[R]_0}{[R]}\) k
= \(\frac{2.303}{40 \ min}\)log \(\frac{100}{100 - 30}\)
= \(\frac{2.303}{40 \ min}\)log \(\frac{10}{7}\)
= 8.918 x 10-3 min-1
Therefore, t1/2 of the decomposition reaction is
t1/2 = \(\frac{0.693}{k}\)
= \(\frac{0.693}{8.918 \times 10^{-3}}\)min
= 77.7 min (approximately)
This post was modified 3 years ago 2 times by admin