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P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar(APB) = ar(BQC).
Areas of Parallelograms and Triangles
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15/07/2021 12:34 pm
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P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD.
Show that ar(APB) = ar(BQC).
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15/07/2021 12:35 pm
ΔAPB and parallelogram ABCD lie on the same base AB and in-between same parallel AB and DC.
ar(ΔAPB) = 1/2 ar(parallelogram ABCD) — (i)
Similarly,
ar(ΔBQC) = 1/2 ar(parallelogram ABCD) — (ii)
From (i) and (ii), we have
ar(ΔAPB) = ar(ΔBQC)
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areas of parallelograms (31)
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