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In Figure, E is any point on median AD of a ΔABC. Show that ar (ABE) = ar(ACE).

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In Figure, E is any point on median AD of a ΔABC. Show that ar (ABE) = ar(ACE).

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Given,

AD is median of ΔABC.

∴ it will divide ΔABC into two triangles of equal area.

∴ ar(ABD) = ar(ACD) — (i)

ED is the median of ΔABC.

∴ ar(EBD) = ar(ECD) — (ii)

Subtracting (ii) from (i)

ar(ABD) – ar(EBD) = ar(ACD) – ar(ECD)

⇒ ar(ABE) = ar(ACE)

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