Notifications
Clear all
D and E are points on sides AB and AC respectively of ΔABC such that ar(DBC) = ar(EBC). Prove that DE || BC.
Areas of Parallelograms and Triangles
1
Posts
2
Users
0
Likes
342
Views
0
16/07/2021 4:13 pm
Topic starter
D and E are points on sides AB and AC respectively of ΔABC such that ar(DBC) = ar(EBC). Prove that DE || BC.
Answer
Add a comment
Add a comment
Topic Tags
1 Answer
0
16/07/2021 4:15 pm
ΔDBC and ΔEBC are on the same base BC and also having equal areas.
∴ they will lie between the same parallel lines.
∴ DE || BC.
Add a comment
Add a comment
Forum Jump:
Related Topics
-
In Figure, ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segment AX DE meets BC at Y. Show that:
3 years ago
-
P and Q are respectively the mid-points of sides AB and BC of a triangle ABC and R is the mid-point of AP, show that:
3 years ago
-
Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that ar (APB) × ar (CPD) = ar (APD)×ar (BPC).
3 years ago
-
In Figure, ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that:
3 years ago
-
In Figure, ABCD is a parallelogram and BC is produced to a point Q such that AD = CQ. If AQ intersects DC at P, show that ar (BPC) = ar (DPQ).
3 years ago
Topic Tags:
class 9 (4384)
,
cbse (15084)
,
ncert (13840)
,
areas of parallelograms (31)
,
triangles (121)
,
Forum Information
- 321 Forums
- 27.3 K Topics
- 53.8 K Posts
- 0 Online
- 12.4 K Members
Our newest member: Stripchat
Forum Icons:
Forum contains no unread posts
Forum contains unread posts
Topic Icons:
Not Replied
Replied
Active
Hot
Sticky
Unapproved
Solved
Private
Closed